• Dark ArcA
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    3 months ago

    If a “safe C++” proposal truly proposes a safe subset, then yes your C++ code would have to opt-in to doing unsafe things. For the purposes of this discussion of a safe subset … the point is moot.

    • FizzyOrange@programming.dev
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      3 months ago

      It’s not moot. The Safe C++ is opt-in to safety. It has to be because otherwise it wouldn’t be compatible with existing C++.

      • Dark ArcA
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        3 months ago

        That’s a laudable difference /s. Using Rust is also an “opt-in” option.