• 21Cabbage@lemmynsfw.com
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    1 year ago

    A literal ton wouldn’t do anything measurable but yeah, adding more material of lower atomic numbers would in theory work considering it’s a fusion engine and wouldn’t exactly scoff at having to break the water molecule before using it.

    Edit: like maybe if there was a star with a bunch of particularly wet planets around it and you somehow deorbited them, since as far as I’m aware the elements heavier than iron are just dead weight, they wouldn’t put out the star or anything.

    • YaBoyMax@programming.dev
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      1 year ago

      I mean, if you add enough iron I believe it would eventually disrupt fusion, but you’d need an incredible amount, far more than you’d ever get from orbiting planets.

      • Red_October@lemmy.world
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        1 year ago

        As I understand it, the problem isn’t the presence of iron, but rather when it starts fusing silicon into iron, as that particular process consumes more energy than it releases, thus eating away at the radiation pressure that keeps the star “held up.”

        • YaBoyMax@programming.dev
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          1 year ago

          I was thinking that the added inert mass would decrease the likelihood of individual fusion reactions as well as eventually overpower the radiation pressure due to its effect on total gravitational force, but honestly I don’t really know what I’m talking about so I could be completely wrong.

        • Ender of Games@sh.itjust.works
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          1 year ago

          Fusing silicon into iron should still release more energy than it takes, fusing iron-56 or heavier should be the point of not gaining energy.

  • e_t_@kbin.pithyphrase.net
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    1 year ago

    Stars have a lot of mass. The Sun loses almost 5 billion tons of mass every second and has enough fuel to last another 4-5 billion years. Adding a single ton of anything would make no appreciable difference. If you were to drop Jupiter into the Sun, it would have an effect, but Jupiter is only 0.09% the Sun’s mass, so the effect would be small.

  • foofiepie@lemmy.world
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    1 year ago

    I suspect the answer here is yes, and there’ll be a lot more hydrogen and oxygen in the star afterwards… but really I’m posting to see what a proper scientist will say.

    Am keen to know if this would pretty much include anything. For example, if I gathered a great enough density of chocolate eclairs in one place, would that become a star?

    • Damaskox@lemmy.world
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      1 year ago

      I believe anything lower from iron will make a star, when enough material added. Of course, one material from iron will give a much smaller lifespan for a star rather than hydrogen only.

      I think that an iron ball wouldn’t start a fusion. Might just jump right to a black hole if you added even more iron 🤔

      • foofiepie@lemmy.world
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        1 year ago

        Damn now my curiosity is piqued.

        So let’s theoretically gather together an almighty ball of iron.

        As you add more, would it’s own gravity cause the density to increase to a point where it would collapse into a black hole?

        Would chocolate eclairs achieve fission? I need to submit these to Randall Munroe.

        • Dr. Coomer@lemmy.worldOP
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          1 year ago

          There is a way to find that out. We can use Schwarzschild radius to find the point at which an objects radius crosses the event horizon and thus becomes a black hole; Rs=2GM/c2, Rs being the Schwarzschild radius, G being the gravitational constant (6.67xe-11), M being the things mass, and c being the speed of light.

        • Damaskox@lemmy.world
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          1 year ago

          As you add more, would it’s own gravity cause the density to increase to a point where it would collapse into a black hole?

          I believe so!

          I assume chocolate is made of lighter elements than iron so yeah, a big chocolate ball enough would become a star!

  • CanadaPlus@lemmy.sdf.org
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    1 year ago

    There’s a lot of oxygen in water by star standards, so keep that in mind. It’s possible the change in metallicity will offset any change to equilibrium temperature, although I don’t really know the details.